Integrand size = 19, antiderivative size = 440 \[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\frac {81 (b c-a d)^2 \sqrt {a+b x} \sqrt [6]{c+d x}}{64 d^3}-\frac {9 (b c-a d) (a+b x)^{3/2} \sqrt [6]{c+d x}}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}-\frac {81\ 3^{3/4} (b c-a d)^{8/3} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{b c-a d} \sqrt [3]{c+d x}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{128 d^4 \sqrt {a+b x} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}}} \]
[Out]
Time = 0.26 (sec) , antiderivative size = 440, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.158, Rules used = {52, 65, 231} \[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=-\frac {81\ 3^{3/4} \sqrt [6]{c+d x} (b c-a d)^{8/3} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \sqrt [3]{b c-a d}+(b c-a d)^{2/3}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} \operatorname {EllipticF}\left (\arccos \left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right ),\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{128 d^4 \sqrt {a+b x} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}}}+\frac {81 \sqrt {a+b x} \sqrt [6]{c+d x} (b c-a d)^2}{64 d^3}-\frac {9 (a+b x)^{3/2} \sqrt [6]{c+d x} (b c-a d)}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d} \]
[In]
[Out]
Rule 52
Rule 65
Rule 231
Rubi steps \begin{align*} \text {integral}& = \frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}-\frac {(15 (b c-a d)) \int \frac {(a+b x)^{3/2}}{(c+d x)^{5/6}} \, dx}{16 d} \\ & = -\frac {9 (b c-a d) (a+b x)^{3/2} \sqrt [6]{c+d x}}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}+\frac {\left (27 (b c-a d)^2\right ) \int \frac {\sqrt {a+b x}}{(c+d x)^{5/6}} \, dx}{32 d^2} \\ & = \frac {81 (b c-a d)^2 \sqrt {a+b x} \sqrt [6]{c+d x}}{64 d^3}-\frac {9 (b c-a d) (a+b x)^{3/2} \sqrt [6]{c+d x}}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}-\frac {\left (81 (b c-a d)^3\right ) \int \frac {1}{\sqrt {a+b x} (c+d x)^{5/6}} \, dx}{128 d^3} \\ & = \frac {81 (b c-a d)^2 \sqrt {a+b x} \sqrt [6]{c+d x}}{64 d^3}-\frac {9 (b c-a d) (a+b x)^{3/2} \sqrt [6]{c+d x}}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}-\frac {\left (243 (b c-a d)^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a-\frac {b c}{d}+\frac {b x^6}{d}}} \, dx,x,\sqrt [6]{c+d x}\right )}{64 d^4} \\ & = \frac {81 (b c-a d)^2 \sqrt {a+b x} \sqrt [6]{c+d x}}{64 d^3}-\frac {9 (b c-a d) (a+b x)^{3/2} \sqrt [6]{c+d x}}{16 d^2}+\frac {3 (a+b x)^{5/2} \sqrt [6]{c+d x}}{8 d}-\frac {81\ 3^{3/4} (b c-a d)^{8/3} \sqrt [6]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right ) \sqrt {\frac {(b c-a d)^{2/3}+\sqrt [3]{b} \sqrt [3]{b c-a d} \sqrt [3]{c+d x}+b^{2/3} (c+d x)^{2/3}}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}} F\left (\cos ^{-1}\left (\frac {\sqrt [3]{b c-a d}-\left (1-\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}{\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}}\right )|\frac {1}{4} \left (2+\sqrt {3}\right )\right )}{128 d^4 \sqrt {a+b x} \sqrt {-\frac {\sqrt [3]{b} \sqrt [3]{c+d x} \left (\sqrt [3]{b c-a d}-\sqrt [3]{b} \sqrt [3]{c+d x}\right )}{\left (\sqrt [3]{b c-a d}-\left (1+\sqrt {3}\right ) \sqrt [3]{b} \sqrt [3]{c+d x}\right )^2}}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.02 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.17 \[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\frac {2 (a+b x)^{7/2} \left (\frac {b (c+d x)}{b c-a d}\right )^{5/6} \operatorname {Hypergeometric2F1}\left (\frac {5}{6},\frac {7}{2},\frac {9}{2},\frac {d (a+b x)}{-b c+a d}\right )}{7 b (c+d x)^{5/6}} \]
[In]
[Out]
\[\int \frac {\left (b x +a \right )^{\frac {5}{2}}}{\left (d x +c \right )^{\frac {5}{6}}}d x\]
[In]
[Out]
\[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {5}{6}}} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\int \frac {\left (a + b x\right )^{\frac {5}{2}}}{\left (c + d x\right )^{\frac {5}{6}}}\, dx \]
[In]
[Out]
\[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {5}{6}}} \,d x } \]
[In]
[Out]
\[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\int { \frac {{\left (b x + a\right )}^{\frac {5}{2}}}{{\left (d x + c\right )}^{\frac {5}{6}}} \,d x } \]
[In]
[Out]
Timed out. \[ \int \frac {(a+b x)^{5/2}}{(c+d x)^{5/6}} \, dx=\int \frac {{\left (a+b\,x\right )}^{5/2}}{{\left (c+d\,x\right )}^{5/6}} \,d x \]
[In]
[Out]